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Parabola: vertex and intercepts

For y = x² − 4x + 3, find the vertex, the x-intercepts and the y-intercept.

Answer
Vertex (2, -1), x-intercepts (1, 0) and (3, 0), y-intercept (0, 3)

Step-by-step

  1. x = −b / (2a) = 4 / 2 = 2
    Vertex x-coordinate of the parabola: x = −b/(2a)
  2. y = 1×2² + -4×2 + 3 = -1
    Substitute back to get the vertex y-coordinate
  3. Δ = b² − 4ac = 16 − 12 = 4
    The discriminant decides how many times the curve crosses the x-axis
  4. x = (4 ± √4) / 2 → 1 and 3
    Quadratic formula
  5. x = 0 → y = 3
    The y-intercept is the constant term c

Why it works

The vertex x-coordinate is −b/2a; substituting back gives y. Intercepts come from factorising for x = 0 and setting x = 0 for the y-intercept.

Common mistakes

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